【Mysql】 查询数据排序以及聚合函数
# 排序# order by 字段# asc 从小到大排序,即升序# desc从大到小排序,即降序# 查询年龄在18到34岁之间的男性,按照年龄从小到大排序select * from students where (age between 18 and 34) and gender=1 order by age;select * from student...
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# 排序
# order by 字段
# asc 从小到大排序,即升序
# desc从大到小排序,即降序
# 查询年龄在18到34岁之间的男性,按照年龄从小到大排序
select * from students where (age between 18 and 34) and gender=1 order by age;
select * from students where (age between 18 and 34) and gender=1 order by age asc;
# 查询年龄在18到34岁之间的男性,按照年龄从小到大排序
select * from students where (age between 18 and 34) and gender=1 order by age desc;
# 查询年龄在18到34岁之间的女性,身高从高到矮排序
select * from students where age between 18 and 34 and gender=2 order by height desc;
# order by 多个字段
# 查询年龄在18到34岁之间的女性,身高从高到矮排序,如果身高相同的情况下按照序列从小到大排序
select * from students where (age between 18 and 34) and gender=2 order by height desc,id desc;
# 聚合函数
# count
# 查询男性有多少人
select count(*) from students where gender=1;
select count(*) as 男性人数 from students where gender=1;
# 最大值
# max
# 查询最大年龄
select max(age) from students;
# 最大值
# min
# 查询最小年龄
select min(age) from students;
# 求和
# sum
# 查询最大年龄
select sum(age) from students;
# 求平均值
# avg
# 查询平均年龄
select avg(age) from students;
# 计算平均年龄
select sum(age)/count(*) from students;
# 四舍五入,保留两位小数
select round(sum(age)/count(*),2) from students;
# 计算男性的平均身高,保留两位小数
select round(sum(height)/count(*),2) from students where gender=1;
# 分组
# 按照性别分组,查询所有的性别
select gender from students group by gender;
select gender,count(*) from students group by gender;
# count(*) 是对前面的分组每组进行求数据
# group_concat
select gender,group_concat(name) from students group by gender;
select gender,group_concat(name,"_",age,"_",id) from students where gender=1 group by gender;
# having
# 查询平均年龄超过30岁的性别,以及姓名
select gender,group_concat(name),avg(age), from students group by gender having avg(age)>30;
# where 和 having 的区别 where在group by 前面 ,having 在group by 后面 ,where 是在对原表进行判断,having是在对判断分组之后的表格
select gender,group_concat(name) from stundents group by gender having count(*)>2;
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